412. Fizz Buzz[E]

https://leetcode.com/problems/fizz-buzz/

Description

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

Solution

1
2
3
4
class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        return [str(i) * (i % 3 != 0 and i % 5 != 0) + "Fizz" * (i % 3 == 0) + "Buzz" * (i % 5 == 0) 
                for i in range(1, n + 1)]

https://leetcode.com/problems/fizz-buzz/solution/

1195. Fizz Buzz Multithreaded[M]

https://leetcode.com/problems/fizz-buzz-multithreaded/

Description

Write a program that outputs the string representation of numbers from 1 to n, however:

  • If the number is divisible by 3, output “fizz”.
  • If the number is divisible by 5, output “buzz”.
  • If the number is divisible by both 3 and 5, output “fizzbuzz”.

For example, for n = 15, we output: 1, 2, fizz, 4, buzz, fizz, 7, 8, fizz, buzz, 11, fizz, 13, 14, fizzbuzz.

Suppose you are given the following code:

1
2
3
4
5
6
7
class FizzBuzz {
  public FizzBuzz(int n) { ... }               // constructor
  public void fizz(printFizz) { ... }          // only output "fizz"
  public void buzz(printBuzz) { ... }          // only output "buzz"
  public void fizzbuzz(printFizzBuzz) { ... }  // only output "fizzbuzz"
  public void number(printNumber) { ... }      // only output the numbers
}

Implement a multithreaded version of FizzBuzz with four threads. The same instance of FizzBuzz will be passed to four different threads:

  1. Thread A will call fizz() to check for divisibility of 3 and outputs fizz.
  2. Thread B will call buzz() to check for divisibility of 5 and outputs buzz.
  3. Thread C will call fizzbuzz() to check for divisibility of 3 and 5 and outputs fizzbuzz.
  4. Thread D will call number() which should only output the numbers.

Solution

1